Q4) When 0.844 grams of Na3(PO4).12H₂O (F.Wt = 380.20 g/mol) reacts with excess of BaCl₂.2H₂O (F.Wt = 244.2 g/mol) how m

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Q4 When 0 844 Grams Of Na3 Po4 12h O F Wt 380 20 G Mol Reacts With Excess Of Bacl 2h O F Wt 244 2 G Mol How M 1 (24.73 KiB) Viewed 14 times

Q4) When 0.844 grams of Na3(PO4).12H₂O (F.Wt = 380.20 g/mol) reacts with excess of BaCl₂.2H₂O (F.Wt = 244.2 g/mol) how many moles of Ba3(PO4)2 are produced (F.wt= 602.20g/mol)? a) 0.0040 mol >) 0.0024 mol c) 0.0025 mol d) 0.0011 mol