- Sanity Check For Ideal Gas As S S Nr In Ncv In Consider A Process Vi Ti From V P To V P Where 1 (17.43 KiB) Viewed 18 times
Sanity check — For ideal gas, AS = S₁ − S₁ = nR In ¼ + nCv In. Consider a process Vi Ti from (V₁, P₁) to (V₂, P₂) where
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Sanity check — For ideal gas, AS = S₁ − S₁ = nR In ¼ + nCv In. Consider a process Vi Ti from (V₁, P₁) to (V₂, P₂) where
Sanity check — For ideal gas, AS = S₁ − S₁ = nR In ¼ + nCv In. Consider a process Vi Ti from (V₁, P₁) to (V₂, P₂) where P₁V₁Y = P₂V, explicitly show that AS = 0. [10 pts]