- Q13 The Electric And Magnetic Fields In A Velocity Selector Are E 2x10 N C And B 1x10 T The Correct Path Of A Positiv 1 (86.87 KiB) Viewed 34 times
please my exam is very near after somedays ,so please solve alll all questions i need your help .please i will give you a like please help me
Q13: The electric and magnetic fields in a velocity selector are E=2x10³ N/C and B-1x10³T. The correct path of a positive charged particle that enters the velocity selector at v=5x10° m/s is: (A) (1) (B) (2) (C) (3) T. Hasan Abdulla Salman Q1: An electron enters a region of crossed uniform electric and magnetic fields as shown. The electric field is directed to the right and the magnetic field is directed into the page. The correct directions of the electric (Fe) and magnetic (FB) forces on the electron are: (B) FE (Right) (C) Fg (Right) (A) FE (UP) FB (Left) FB (Left) FB (Right) FB (Right) An electron moving with a velocity-5.0x107 m/s f enters a region of space where perpendicular electric and a magnetic fields are present. The electric field is - 1. What magnetic field will allow the electron to go through the region without being deflected? +5.0×104T - -2.0*10-4 T ©-+2.0-104 T --2.0-104 T - +2.0-104 T BIZZ Q15: A proton is moving with a velocity of 3.51x105 m/s enters a velocity selector of electric field E-2464 N/C. The magnitude of magnetic field B (in mT) required to have the proton pass the velocity selector without any deflection is: (A) 5.0 (B) 6.0 (C) 0.0 (D) 9.0 Q12: A charged positive ion has a charge (+q) enters a velocity selector with speed v=2x10° m/s as shown in the figure. The magnitude of the electric field ( in N/C) so the ion passes the velocity selector without any deflection is: (A)2x10³ (B) 4x10³ (C) 6x 10³ (D) (4) O O O ++ (D) FE (Left) FB (Left) +q O O Proton xB X Bout O O O (1) ++ (E) Non of them 12 ewit Electron (E) Fg (Left) UpA 10 OB (E) 7.0 (2) Right Bout=2 mT +++ 6 O O O O O O (D) 8x10³ E