- Question 1 A Tall Water Tank P 998 Kg M Discharges Through A Well Rounded Orifice To Hit A Plate As Shown In Figu 1 (87.17 KiB) Viewed 21 times
- Question 1 A Tall Water Tank P 998 Kg M Discharges Through A Well Rounded Orifice To Hit A Plate As Shown In Figu 2 (86.19 KiB) Viewed 21 times
- Question 1 A Tall Water Tank P 998 Kg M Discharges Through A Well Rounded Orifice To Hit A Plate As Shown In Figu 3 (88.29 KiB) Viewed 21 times
Question 1. A tall water tank (p = 998 Kg/m³) discharges through a well-rounded orifice to hit a plate, as shown in Figure 1. The orifice's diameter is d = 4 cm. (1) (2) F d=4 cm Figure 1: Water tank. Answer the following questions: (a) Show that the velocity V₂ at the outflow of the orifice (Point 2 in Figure 1) is related to the force F required to hold the plate and the orifice diameter d through (V₂)² = 4F ρπα2 (b) Determine the depth h of the water tank if the force F required to hold the plate is 160N. You can neglect any friction head loss between Points 1 and 2. (c) Determine the depth h of the water tank if the friction head loss be- tween Points 1 and 2 is 0.5 m. You can still consider that the force F required to hold the plate is 160 N. [10 marks] [10 marks] [10 marks]
q' = & co (T4 - Tur) q" = hr(Ts - Tsur) q hr = go(Ts + Tsur)(T² + Tur) q" = h(Ts - T) dT q' = -k dx ac J=-D Әх *(x)+(@)-3() + +4= PCp at ӘT ду ду дz ат 10 (krar) + 110 (80) + 2 (10) + k +9=PCp rər дz Ət 1 Ә + r2 Jr Ər r2 sin20 дф 11(0) - (1) kr² 1 Ә ӘТ ат + k sin 0- +q=PCp r2 sin 0 80 20 Ət Ә Q-w, -w - ^ [ (i++12+9=) my] W, V2 + - Jos( h+-V2 + 9z p(V. n)dA dû P + p(V.V) = V . (kVT) + Ф dt 82C 82c 82c + +R ах2 дуг (18 ac 1 02C 82C + + R r2 до2 дz2 1 Ә r2 sin 0 80 ac at ac at ac Ət = D = D = D rər 10 r2 ar ar ar + + д22 + sin 0. 20 + 1 82C r2 sin2 0 82 (13) (14) (15) (16) (17) (18) (19) (20) (21) (22) (23) + R (24)
ac Ət ac Ət ac Ət q" = xo(T4 - Tur) q' = hr(Ts - Tsur) hr = €o(Ts + Tsur)(T² + Taur) q' =h(Ts - To) dT q' = -k dx ac J=-D дх Ә ӘT 3(7)-5 (3)+3 (4) + k +q=PCp 𐐀х ду ду дz Ət 10 10 ат 18 (7)-18 (3)-3(*) kr + + k +4=PCp rər Ər р2 аф дz 10 (1) + kr2 1 Ә ат k r2 ar ar r2 sin20 дф аф ат + 1 Ә r2 sin 0 80 k sin 0. +q=PCp Ət Ә Q - W - W, Palme (ksinger) * UL (*+^v* + *z) v] + J (* + +v* ) +9z p(V.n)dA <= =V2 gz Ət CV 1 2 dû P + p(V . V) = V . (kVT) + Ф dt 82C 22c 82C + + R дz2 +R = D = D = D + дх2 дуг 10 ac ar ( ar 10 Ər p2 ac Ər + 1 820 r2 аф2 1 Ә r2 sin 0 80 + 82C + дz2 ӘC 20 sin 0 + ӘT Ət 1 82c r2 sin² 0 0Ф2 (13) (14) (15) (16) (17) (18) (19) (20) (21) (22) (23) + R (24)