b) Table 2. Contraction in mm of smooth muscle by an agonist in thepresenceof increasingconcentrationsof anantagonist. A

Post by **answerhappygod** » Mon May 23, 2022 1:50 pm

: B Table 2 Contraction In Mm Of Smooth Muscle By An Agonist In Thepresenceof Increasingconcentrationsof Anantagonist A 1 (155.23 KiB) Viewed 20 times

Need answers in 60 minutes. I will give thumbs up
b) Table 2. Contraction in mm of smooth muscle by an agonist in thepresenceof increasingconcentrationsof anantagonist. AntagonistBconcentration Agonistcon centration =0 = 1x10-10M = 1x10°M = 1x108m = 1x10²M 0 0 1 0 1 0 0 0 0 1 Oo oo oo 0 0 1x10''M 3x10''M 1x10'M 3x10'M 1x10®M 3x10 M 1x10 M 3x10 PM 1x10CM 3x10CM 1x10 M 3x10 M 1x10 M 3x10 M 1x10 M 0 2 4 9 17 24 29 30 30 30 30 30 30 30 30 2 4 10 18 25 28 29 30 30 1 3 6 14 22 27 29 29 2 7 15 22 27 1 1 2 7 15 22 27 28 29 30 29 30 30 30 30 30 30 30 29 30 30 i) Plotaconcentration- responsecurvethatshowstherelationshipbetweenagonistconcentratio nand%maximumeffectatEACHoftheconcentrations of antagonist B shown in Table 2 (plot all the data onone graph). ii) Calculatethe EC50withoutantagonistandwithEACHoftheconcentration sofantagonistused. CalculatetheDoseRatioforEACHoftheantagonistc oncentrations. Writedownyouranswersandshowyourworkings. iii) OnaseparatepieceofgraphpaperconstructaSchildPlot.Fromthisplot,c alculatethepKzvalue oftheantagonist.DefinepKB.