Problem 9: (30 points) Two long straight wires carrying 3 A of conventional current are connected by a three- quarter-ci

Post by **answerhappygod** » Mon May 23, 2022 12:46 pm

: Problem 9 30 Points Two Long Straight Wires Carrying 3 A Of Conventional Current Are Connected By A Three Quarter Ci 1 (21.44 KiB) Viewed 19 times

: Problem 9 30 Points Two Long Straight Wires Carrying 3 A Of Conventional Current Are Connected By A Three Quarter Ci 2 (21.44 KiB) Viewed 19 times

: Problem 9 30 Points Two Long Straight Wires Carrying 3 A Of Conventional Current Are Connected By A Three Quarter Ci 3 (19.15 KiB) Viewed 19 times

: Problem 9 30 Points Two Long Straight Wires Carrying 3 A Of Conventional Current Are Connected By A Three Quarter Ci 4 (16.87 KiB) Viewed 19 times

: Problem 9 30 Points Two Long Straight Wires Carrying 3 A Of Conventional Current Are Connected By A Three Quarter Ci 5 (18.82 KiB) Viewed 19 times

Problem 9: (30 points) Two long straight wires carrying 3 A of conventional current are connected by a three- quarter-circular arc of radius 0.0428 m. An electric field is also present in this region, due to charge not shown on the drawing. An electron is moving to the right with a speed of 5x 105 m/s as it passes through the center C of the arc, and at that instant the net electric and magnetic force on the electron is zero. (Consider the charge of the electron: q = -1.6×10¹9 C) Radius R C.P Electron
1. (2 points) The magnitude of the magnetic field due to the straight segments at the center of the arc is: B straght 2. (1 point) The magnetic field due to the arc can be calculated using the formula number (refer to the formula sheet 3. (1 point) The magnitude of the magnetic field due to the three-quarter-circular are at the center of the arc can be calculated using: (0.0428) (0.0428) (0.0428) 10×2×²×(3) (0.0428) 4. (4 points) The magnitude of the magnetic field due to the three-quarter-circular arc at the center of the arc is: ↑ B are
5. (3 points) The direction of the magnetic field due to the three-quarter-circular arc at the center of the arc in pointing to: Ointo the page Cout of the page Oupward Downward 6. (1 point) The magnetic force acting on the electron calculated using the formula number (refer to the formula sheet) 0 7. (1 point) The magnitude of the magnetic force on the electron at the center of the arc can be calculated using O(1.6 x 10 )x(5x 10) (3.3 × 10 ) x (cos(90)) x O(1.6× 10-1)×(5 x 10°) (3.3 x 10 )x(sin(45)) O(1.6× 10-¹)×(5 x 10) (3.3 × 10 )x(sin(0)) O(1.6× 10-¹)×(5 x 10) x (3.3 × 10 )x(sin(90))
8. (4 points) The magnitude of the magnetic force on the electron at the center of the arc is F magnetic 9. (5 points) The direction of the magnetic force on the electron at the center of the arc is pointing to: Oright OLeft Oupward ODownward 10. (4 points) The magnitude of the electric force on the electron at the center of the arc is: F electric 11.(4 points) The direction of the electric force at the center of the arc is pointing to: Oright OLeft Oupward ODownward