Consider an infinitely long wire of charge carrying a positive charge density of A. The electric field due to this line

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Consider an infinitely long wire of charge carrying a positive charge density of A. The electric field due to this line

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Consider An Infinitely Long Wire Of Charge Carrying A Positive Charge Density Of A The Electric Field Due To This Line 1
Consider An Infinitely Long Wire Of Charge Carrying A Positive Charge Density Of A The Electric Field Due To This Line 1 (66.3 KiB) Viewed 14 times
Consider an infinitely long wire of charge carrying a positive charge density of A. The electric field due to this line of charge is given by E= 2ke-f 1 A -, where is a unit vector directed radially outward T Υπερτ from the infinitely long wire of charge. Hint a. Letting the voltage be zero at some reference distance (V(ro) = 0), calculate the voltage due to this infinite line of charge at some distance r from the line of charge. Give your answer in terms of given quantities (A,ro,r) and physical constants (ke or Eo). Use underscore ("_") for subscripts and spell out Greek letters. Hint for V(r) calculation V(r) = b. There is a reason we are not setting V(ro) = 0 as we normally do (in fact, in general, whenever you have an infinite charge distribution, this "universal reference" does not work; you need a localized charge distribution for this reference to work). Which of the following best describes what happens to potential as roo? (That is, what is V(ro), with our current reference, V(ro) = 0?) OV(r → ∞) oscillates within a bounded range (no well-defined limit but does not diverge). OV(ro) increases to +∞o without limit. OV(ro) asymptotically approaches a finite value. OV(r- →∞) decreases to -∞o without limit. =
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