= Problem 1 (30 points) Consider two objects of masses mı= 6.033 kg and m2 = 2.593 kg. The first mass (m2) is traveling

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Problem 1 30 Points Consider Two Objects Of Masses Mi 6 033 Kg And M2 2 593 Kg The First Mass M2 Is Traveling 1 (112.46 KiB) Viewed 14 times

Problem 1 30 Points Consider Two Objects Of Masses Mi 6 033 Kg And M2 2 593 Kg The First Mass M2 Is Traveling 2 (31.15 KiB) Viewed 14 times

Problem 1 30 Points Consider Two Objects Of Masses Mi 6 033 Kg And M2 2 593 Kg The First Mass M2 Is Traveling 3 (39.12 KiB) Viewed 14 times

Problem 1 30 Points Consider Two Objects Of Masses Mi 6 033 Kg And M2 2 593 Kg The First Mass M2 Is Traveling 4 (106.08 KiB) Viewed 14 times

Problem 1 30 Points Consider Two Objects Of Masses Mi 6 033 Kg And M2 2 593 Kg The First Mass M2 Is Traveling 5 (78.12 KiB) Viewed 14 times

Problem 1 30 Points Consider Two Objects Of Masses Mi 6 033 Kg And M2 2 593 Kg The First Mass M2 Is Traveling 6 (86.97 KiB) Viewed 14 times

i need answers for all parts please do in clear and neat handwriting as soon as possible please correct I'll rate it
= Problem 1 (30 points) Consider two objects of masses mı= 6.033 kg and m2 = 2.593 kg. The first mass (m2) is traveling along the negative y-axis at 46.28 km/hr and strikes the second stationary mass m2, locking the two masses together. a) (5 Points) What is the velocity of the first mass before the collision? V mize V. m/s m1 > b) (3 Points) What is the velocity of the second mass before the collision? = V. m2 > m/s c) (1 Point) The final velocity of the two masses can be calculated using the formula number: (Note: use the formula- sheet given in the introduction section) d) (5 Points) What is the final velocity of the two masses? =< > m/s e) (4 Points) Choose the correct answer:
(5 points) In a harmonic oscillator, the spacing energy AE between the quantized energy levels is 4 eV. What is the energy of the ground state? a. leV O b. 4 eV C. 2 eV O d. 0 eV
(5 points) A 2200 kg car traveling at 30 m/s collides with another 2200 kg car that is at rest. The two bumpers lock and the cars move forward together. What is their final velocity? a. 10 m/s s O b. 0 m/s c. 15 m/s O d. 30 m/s .
Problem 2 (30 points) A microscopic spring-mass system has a mass m = 8 x 10-26 kg and the energy gap between the 2nd and 3rd excited states is 8 eV. a) (2 points) Calculate in joules, the energy gap between the 1st and 2nd excited states: E= J b) (2 points) What is the energy gap between the 4th and 7th excited states: E= eV c) (1 point) To find the energy of the ground state, which equation can be used ? (check the formula_sheet and select the number of the equation) d) (1 point) Which of the following substitutions can be used to calculate the energy of the ground state? O(6.582 x 10-16)(8) OLS 8 O2 x 8 (6.582x10-16) 2 2 O(6.582 x 10-16)(8)
e) (3 points) The energy of the ground state is: E= eV f) (1 point) To find the stiffness of the spring, which equation can be used ? (check the formula_sheet and select the number of the equation) g) (1 point) Which of the following substitutions can be used to calculate the stiffness of the spring? 2 8 (8 x 10-26 llos -) ? 6.582x10-16 8 6.582x10-16 8x10-26 2 O(8 x 10-26) (6.582 x 10-16)2 O(8 x 10-26) (8) O(8 x 10-26)( 6582x10-10 8 O2 (6.582x10-16) 2 8 6.582x10-16 8x10-26
h)(3 points) The stiffness of the spring : is: K = (N/m) i) (2 point) What is the smallest amount o vibrational energy that can be added to this system? E = Jev j) (5 points) What is the wavelength of the smallest energy photon emitted by this system? I = m k) (2 points) If the stiffness of the spring increases, the wavelength calculated in the previous part 1) (2 points) If the mass increases, the energy gap between successive energy levels