The rate of adsorption and the rate of desorption is given by: rate of adsorption = k1 [A](1 - 0) = rate of desorption k
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The rate of adsorption and the rate of desorption is given by: rate of adsorption = k1 [A](1 - 0) = rate of desorption k
The rate of adsorption and the rate of desorption is given by: rate of adsorption = k1 [A](1 - 0) = rate of desorption kze where: kz = rate constant for adsorption, ka = rate constant for desorption, 8 = fraction of surface site occupied by molecule A, [A] = concentration of molecule A in the fluid phase At equilibrium: rate of adsorption = rate of desorption = And the equilibrium constant is: K= Also: 0 = ki [A] ka + k [A] Given those facts about the Langmuir isotherm, solve the following problem: Chloroethane from the gas phase is adsorbed on a sample of charcoal at 273.15K. The mass adsorbed for each concentration in the gas phase is 1.17 x 10-3 2.94 x 10-3 5.87 x 10-3 1.17 x 10-2 1.76 x 10-2 [C2H5Cl] (mol L ) 3.0 3.8 4.3 4.7 4.8 Mass adsorbed (grams) a.) Find the value of e for each concentration b.) Find the value of the equilibrium constant, K