2 a) What is the definition of linear momentum? The engine of an unpowered train of mass 700 kg is rolling at a constant

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2 A What Is The Definition Of Linear Momentum The Engine Of An Unpowered Train Of Mass 700 Kg Is Rolling At A Constant 1 (32.07 KiB) Viewed 20 times

2 A What Is The Definition Of Linear Momentum The Engine Of An Unpowered Train Of Mass 700 Kg Is Rolling At A Constant 2 (23.2 KiB) Viewed 20 times

2 A What Is The Definition Of Linear Momentum The Engine Of An Unpowered Train Of Mass 700 Kg Is Rolling At A Constant 3 (44.77 KiB) Viewed 20 times

2 A What Is The Definition Of Linear Momentum The Engine Of An Unpowered Train Of Mass 700 Kg Is Rolling At A Constant 4 (38.34 KiB) Viewed 20 times

2 a) What is the definition of linear momentum? The engine of an unpowered train of mass 700 kg is rolling at a constant speed on a level track, as shown in Fig. 2.1. The engine collides with a stationary truck of mass 900 kg, and joins with it. The wo train lock together and continue to move at 8 ms-1 after the collision mogne 100 b) Fig. 21 Calculate the momentum of engine and truck after and before the collision c) Calculate the speed in km/hour of the engine before the collision. d) Calculate the kinetic energy of each train before and after the collision 0) Explain why there is a difference in the total kinetic energy of the engine and truck before and after the collision 1) Using the principle of conservation of momentum, calculate the speed of the joined engine and truck immediately after the collision
Electricity V=IR Power = VI R = R1 + R2 + R3 1 + 1+1 R: R2 R3 R Capacitors Area > Permittivity C= Gap Size AQ = 1 At Q=VC C Charge- Volts Energy = Work = QV Capacitor charging V = V.(1 - IT #ek Time Constant C= RC Vo R e RC Waves v = fx The phase difference o = 27 ) y = A sin wt or y = A sin 20 ft y = A sin 217(f. -5)
Linear Angular 0 S V w a a dw Q V = u + at w = wo + at V = u' + 2as w = wo" + 2a0 s = ut + zat? 0 = Wot + Wat" S = 1 (u + v)t = /2 (Wow, t dv das d2e dt dt2 dt dt2 Mass m Moment of Inertia I (kg m) F = ma (N) Torque T (Nm) = Fr= la E (Joules) = m v? E (Joules) = 1 w Momentum p = mv (kgms L= I w (kg m?s') ) Power P (Watts) = Fv (N P (Watts) = T W (Nms') ms) Impulse = A (mv) = F At Δ( Ιω) = ΤΔt SHM Period is T = 2n JĘ for as a pendulum, or T = 21 vete for a mass spring system. k is the stiffness of a spring, or the force required to give unit extension.
Trigonometry and Algebra b Sin 8 Sin A Sinc For a right angle triangle, c = a + b2 For all triangles c? = a + b2 - 2 a b Cos C Cose + Sin e = 1 Differentiation d(ax"=0) = nax-1 Integration Sax"dx = **1 ***1 +C dx ac If a x2 + bx+c=0 then -bt X = Za Motion Force = mass x acceleration Potential Energy = mgh Kinetic Energy = mv Work = Energy Power is rate of work Momentum = Mass x Velocity Impulse = Force x Time Acceleration due to gravity (9) = -9.8 ms? w = 2 T f = (2T)/T Moment of Inertia for a point mass, I =mr Moment of Inertia for disc, I amr? Moment of Inertia for a sphere, I amr Moment of Inertia for a rod pinned at one end I am Moment of Inertia for a rod pinned in the middle I am For a set of masses rotating on the same shaft, I = 1,+ 12+13+14 Acceleration due to gravity (g) = -9.8 ms?