4 Alcohol S, has the molecular formula C6H140. Reaction of S with hot acidified potassium dichromate produces compound T
-
- Site Admin
- Posts: 899603
- Joined: Mon Aug 02, 2021 8:13 am
4 Alcohol S, has the molecular formula C6H140. Reaction of S with hot acidified potassium dichromate produces compound T
4 Alcohol S, has the molecular formula C6H140. Reaction of S with hot acidified potassium dichromate produces compound T, C6H12O2. Dehydration of s produces an alkene U, C6H12. Strong oxidation of U, forms 2-methylbutanoic acid as one of the products. (a) Draw the structures of S, T and U. [3] (b) Write the equation when 2-methylbutanoic acid reacts with NaHCO3. State the observation of the reaction. [3]