Given the equation below, how many grams of PCls are needed to react with 75 g of CH3OH? 2 CH3OH + PC15 – 2 CH3CI + 2 PO

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Given the equation below, how many grams of PCls are needed to react with 75 g of CH3OH? 2 CH3OH + PC15 – 2 CH3CI + 2 PO

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Given The Equation Below How Many Grams Of Pcls Are Needed To React With 75 G Of Ch3oh 2 Ch3oh Pc15 2 Ch3ci 2 Po 1
Given The Equation Below How Many Grams Of Pcls Are Needed To React With 75 G Of Ch3oh 2 Ch3oh Pc15 2 Ch3ci 2 Po 1 (16.88 KiB) Viewed 21 times
Given the equation below, how many grams of PCls are needed to react with 75 g of CH3OH? 2 CH3OH + PC15 – 2 CH3CI + 2 POCI; + H2O molar masses: CH3OH: 32.05 g/mol PC15: 208.22 g/mol CH3Cl: 50.49 g/mol POC13: 153.32 g/mol H20: 18.02 g/mol
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