QUESTION 9 X2Y2 + (5/2)02(9) ---> 2XO2 + y20 AH =-130 kJ X(s) + O2(9) ---> XO2 AH = -390 kJ Y2(g) + (1/2)02(9) ---> 20 A

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answerhappygod
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QUESTION 9 X2Y2 + (5/2)02(9) ---> 2XO2 + y20 AH =-130 kJ X(s) + O2(9) ---> XO2 AH = -390 kJ Y2(g) + (1/2)02(9) ---> 20 A

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Question 9 X2y2 5 2 02 9 2xo2 Y20 Ah 130 Kj X S O2 9 Xo2 Ah 390 Kj Y2 G 1 2 02 9 20 A 1
Question 9 X2y2 5 2 02 9 2xo2 Y20 Ah 130 Kj X S O2 9 Xo2 Ah 390 Kj Y2 G 1 2 02 9 20 A 1 (16.6 KiB) Viewed 8 times
QUESTION 9 X2Y2 + (5/2)02(9) ---> 2XO2 + y20 AH =-130 kJ X(s) + O2(9) ---> XO2 AH = -390 kJ Y2(g) + (1/2)02(9) ---> 20 AH = -280 kJ + What is the AH° for the following reaction? 2X(s) + Y2(9) ---> X2Y2 AH = ??? kJ 1190 kj -540 kJ O-8.0x102 Kj -930 kJ
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