Question One (a) How many degrees of freedom will be present in a solution of sodium sulphate in equilibrium with water

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Question One A How Many Degrees Of Freedom Will Be Present In A Solution Of Sodium Sulphate In Equilibrium With Water 1 (123.16 KiB) Viewed 8 times

Question One (a) How many degrees of freedom will be present in a solution of sodium sulphate in equilibrium with water vapour? (2) (b) Calculate the density (in kg m?) of paraffin, if a glass capillary of diameter 0.25 mm dipped in paraffin of the surface tension 0.0245 Nm - rises to a height of 4 cm. The contact angle of paraffin with glass is 28. (4) (c) Use the Kelvin equation to calculate the vapour pressure (in mmHg) of a spherical droplet of water with a diameter of 1.75 x 10-6 cm at 30.0 °C. The vapour pressure of bulk water at that temperature is 31.8 mmHg and its density is 0.998 g cm-3. The surface tension of water is 71.18 Dyne cm 1 at this temperature. Note: 1 N m1 = 1000 Dyne cm-1 (5) Question Two The figure shows a phase diagram of two components A and B. Describe what happens at point x where the mole fraction of component A is 0.75 as the temperature is decreased until the ntire solution is solid. In your explanation indicate phases are present, composition and which phase has the greatest number of moles. 250 200 Temperature M 150 1004 0.0 0.2 0.4 0.6 0.8 1.0 Mole Fraction A (5) 2/4