- 8 Fe2 Excess Iron Iii Was Reduced To Iron Ii By 0 344 G Of Chromium Hydroxide According To The Following Unbalance 1 (22.75 KiB) Viewed 8 times
8. . Fe2 Excess Iron(III) was reduced to iron(II) by 0.344 g of chromium hydroxide according to the following unbalance
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8. . Fe2 Excess Iron(III) was reduced to iron(II) by 0.344 g of chromium hydroxide according to the following unbalance
8. . Fe2 Excess Iron(III) was reduced to iron(II) by 0.344 g of chromium hydroxide according to the following unbalance reaction: Cr(OH);" (aq) Fe(aq) (aq) + chromium oxide compound(aq) Fer from the above reaction was isolated and titrated with potassium sulfite. It took an average of 23.50 mL of 0.2557 MK250, to reach the endpoint. The titration reaction is. Fe? So, SO4 (ou . + (oul (0) - Fe3 (aq) Based on this information, what is the possible chromium oxide product? b. CrO2 C. Cr dcrog 2 a. Cro e. Cr2O74 f. Cr206