A 45.00 mL portion of olive oil (d=0.017 kg/L) was added to a mixture weighing 250 g. By mass, the mixture contains 56.9

[answerhappygod]

A 45.00 mL portion of olive oil (d=0.017 kg/L) was added
to a mixture weighing 250 g. By mass, the mixture contains 56.9%
water (d=0.99704 g/mL), 23.1% salt, 15.0% of suspended solids, and
5.0% sugar. Find the percent composition (% w/w) of the final
mixture. (Edit: This is only
what the problem states. Before finding the percent composition of
the final mixture, the instruction is to determine the mass of
components of original mixture.)