3 SPH4U May 18, 2022 V O new m Name 2. When serving a tennis ball, a player hits the ball when its velocity is zero (at

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3 Sph4u May 18 2022 V O New M Name 2 When Serving A Tennis Ball A Player Hits The Ball When Its Velocity Is Zero At 1 (47.82 KiB) Viewed 10 times

3 Sph4u May 18 2022 V O New M Name 2 When Serving A Tennis Ball A Player Hits The Ball When Its Velocity Is Zero At 2 (47.82 KiB) Viewed 10 times

3 SPH4U May 18, 2022 V O new m Name 2. When serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racquet exerts a force of 540 N on the ball for 5.00 ms, giving it a final velocity.of 45.0 m/s. Using these data, find the mass of the ball (TA: 2) 3. Sam is driving Car A at 45.0 km/hr East. Braydon is driving Car B is at 55.0 km/he North. The masses of the cars are M. - 2200 kg and Ma-3750 kg. They collide (nobody is burt!) and the wreckage sticks together. a) Determine the direction the wreckage moves (angle 0 in the diagram). (T1:2) b) How far does the wreckage slide before coming to stop? Assume the coefficient of kinetic friction is 0.65.(T/1:2) un we yuz, UF, e me Verz th 550x1000x 300 mi Via Vfx (mitmal 2200X12.5ms Vfx2.2+3750) 2750 E 215.2 » Uk Sing= 9.5 5950 10-5 [E36 3Vfx miny z my 5950 my Viy=Vfy (m₁-3760×15.2 4. In the diagram below, the natural length of the spring is 1.00 m. Arshia carefully placed block A on the plane and the length of the spring is now 0.75 m. Tavan, then launched block B down the incline with an initial speed vo-4.00 m/s. The initial distance, d between the blocks is 1.50 m. Find the length of the spring at its maximum compression. (T/1: 4) -0.40, -0.50, M₁-1.75 kg. My-2.45 kg: k-39.35 N/m A lox 1.5 Sin 35+ (39:35 ) x ² = (4.00) +1.75x10x00 -6.42 + 19.6x² = 9 35.0 x=50-7 x₂ 0.8m. 5. You are asked to design a roller coaster that looks like the one shown in the diagram below. The track will be frictionless and the car will start from rest from a height h. Take the radius of the loop ask. Calculate the minimum height h required to ensure that the car can successfully loop-the-loop. Express your answer in terms of R. (Hint: you may have to think about UCM) (A:5) m² +mgh = my ² R Rm² +mgh, my² R +mgh ₂2 m² mit Pe 2-mgh) R22-mg (2R+h) 1-50-% 10.5