Height Versus Time 1.200 1.000 0.800 0.600 0.400 y=(0,797m) +(-0.48 m/s) +(-9.61 m/s) t 0.200 Tangent line at t= 0.150 s
-
- Site Admin
- Posts: 899603
- Joined: Mon Aug 02, 2021 8:13 am
Height Versus Time 1.200 1.000 0.800 0.600 0.400 y=(0,797m) +(-0.48 m/s) +(-9.61 m/s) t 0.200 Tangent line at t= 0.150 s
Height Versus Time 1.200 1.000 0.800 0.600 0.400 y=(0,797m) +(-0.48 m/s) +(-9.61 m/s) t 0.200 Tangent line at t= 0.150 s 0.000 Height (m) y=(-1.92 m/s) t+ ( 0.905 m) 0.000 0.050 0.100 0.150 Time (sec) Fit Lines 0,200 Tangent 0.00 -0.50 -1.00 -1.50 -2.00 -2.50 -3.00 -3.50 Velocity (m/s) 0.250 Data Set 1 Velocity Versus Time v=(-9.62 m/s) t+ (-0.49m/s) Area -0.420 m 0.050 • 0.000 Area 0.100 0.150 0.200 Time (sec) Show Data 0.250
400 Examine Velocity +(-0.48 m/s) t +½ (-9.61 m/s) t² 200 Tan Slope of height graph at time selected: y=(-1.92 m/s) t+ (0.905 m) Velocity at time selected: 000 0.000 0.050 0.150 0% difference: 0.100 Time (sec) Examine Displacement Initial time and height: Final time and height: Displacement during time interval t; to t: Area under velocity-time graph from t; to t₁: % difference: Examine Acceleration Slope of velocity graph: Local gravitational acceleration: % difference: Report Time selected: -2.50 -3.00 -3.50 t₁ = v = (-9.62 my' (t₁) = Area = -0.420 m 0.050 0.150 -1.92 v (t₁) = -2.00 % diff= -4.08 Time (sec) Y₁ = 0.800 y₁ = 0.600 m Ay = -2.00 A= -0.420 m % diff=130.57 % v' = -9.62 m/s² g= -9.80 m/s² -1.85 % 0.000 t = -0.70 t= -2.00 sec sec % diff= sec m/s m/s 2% E E 0.25