. 4. A parallel-plate capacitor has a plate area of 0.2 m2 and a plate separation of 0.1 mm. To obtain an electric field

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. 4. A parallel-plate capacitor has a plate area of 0.2 m2 and a plate separation of 0.1 mm. To obtain an electric field

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4 A Parallel Plate Capacitor Has A Plate Area Of 0 2 M2 And A Plate Separation Of 0 1 Mm To Obtain An Electric Field 1
4 A Parallel Plate Capacitor Has A Plate Area Of 0 2 M2 And A Plate Separation Of 0 1 Mm To Obtain An Electric Field 1 (12.6 KiB) Viewed 12 times
4 A Parallel Plate Capacitor Has A Plate Area Of 0 2 M2 And A Plate Separation Of 0 1 Mm To Obtain An Electric Field 2
4 A Parallel Plate Capacitor Has A Plate Area Of 0 2 M2 And A Plate Separation Of 0 1 Mm To Obtain An Electric Field 2 (27.85 KiB) Viewed 12 times
. 4. A parallel-plate capacitor has a plate area of 0.2 m2 and a plate separation of 0.1 mm. To obtain an electric field of 2.0 x 106 V/m between the plates, calculate the magnitude of the charge on cach plate

Explanation of your approach to the problem, why are using the equation you are using. Is your approach consistent with frameworks of physics we have learned in class? This part should be answered with 2 to 3 short sentences that justifies your starting point and puts the problem in context. 3/10 Draw a relevant picture or diagram 1/10 Develop a model and mathematical solution and obtain a symbolic expression for the quantity a you are finding (6/10) Ellenblame
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