x = 16 - 6 2. The position of a body moving along a straight line is given by where x is in meters and t in seconds a) F

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answerhappygod
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x = 16 - 6 2. The position of a body moving along a straight line is given by where x is in meters and t in seconds a) F

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X 16 6 2 The Position Of A Body Moving Along A Straight Line Is Given By Where X Is In Meters And T In Seconds A F 1
X 16 6 2 The Position Of A Body Moving Along A Straight Line Is Given By Where X Is In Meters And T In Seconds A F 1 (73.9 KiB) Viewed 14 times
X 16 6 2 The Position Of A Body Moving Along A Straight Line Is Given By Where X Is In Meters And T In Seconds A F 2
X 16 6 2 The Position Of A Body Moving Along A Straight Line Is Given By Where X Is In Meters And T In Seconds A F 2 (39.85 KiB) Viewed 14 times
x = 16 - 6 2. The position of a body moving along a straight line is given by where x is in meters and t in seconds a) Find the position of the body at t=1s (10m) b) At what times does the body pass the origin? (Os, 2.678) c) Calculate the average velocity of the body between t = 0 and 2 seconds. (4m/s) d) Find the velocity of the object at any time t. (V 16. 121) e) What is velocity at t=0?att - 2s? (16m/s, -6m/s) f) At what times and positions will the body be at rest? (1.338, 10.6m) g) Find the acceleration of the body at any time t. (-12m/s) h) When is the acceleration of the body zero? (never)

1) Using the data calculated from a-h, plot a vst, v vst, and xvs t. al (m/s) t(s) (m/s) t(s) X (m) t(s) j) During what time interval(s) is the body "speeding up" i.e. accelerating)? (t>1.33) k) During what time interval(s) is the body "slowing down" (i.e. decelerating)? (0<=< 1.33)
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