Measured Values Object Distance Do 62 Cm 320 Cm Image Distance Di 1 62 1 320 1 1 F 51 94 Cm Calculated Value Foca 1 (35.86 KiB) Viewed 18 times
Measured Values Object Distance Do 62 Cm 320 Cm Image Distance Di 1 62 1 320 1 1 F 51 94 Cm Calculated Value Foca 2 (32.25 KiB) Viewed 18 times
Measured values: Object distance do = 62 cm 320 cm image distance di = 1/62+1/320=1/1 f= 51.94 cm Calculated value: focal length f= 51 cm Comment on how well your measure and calculated values off agree. I think my measure and calcualtion, boyth are quite similar D. MAGNIFICATION You should have observed above that the size of the image changes depending on the position of the object. The magnification of the image is defined as the ratio of the image size to the object size, but it is also related to the image and object distances by: M=d/d. (2) Dan AE
Using the equations (1) and (2), show that the image will be the same size as the object when de = di (.e. just substitute do = d). Then show that this occurs when do = di = 2f Is this conclusion confirmed by the simulation when do = di = 2f?
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