Using standard reduction potentials from the following table, calculate the standard reaction free energy AGº for the fo

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Using Standard Reduction Potentials From The Following Table Calculate The Standard Reaction Free Energy Ago For The Fo 1 (184.7 KiB) Viewed 10 times

Using standard reduction potentials from the following table, calculate the standard reaction free energy AGº for the following redox reaction. 3Cu" (aq) + Mnoz (aq) +2H20 (1) 3Cu2+ (aq) + MnO2 (s) +401 + TABLE 20.1 Standard Electrode Potentials at 25°C Reduction Half-Reaction Fylg) +20 E 2.8 1.73 1.68 1.62 1.5 1.56 + 1.44 1.31 1.3: 1.2: 1.2 - 1.26 1.03 1.00 H,O, (aq) + 2 H(aq) + 2 e PbO (s) + 4 H(aq) + SO-(aq) + 2 e 02 Mnoc (aq) + 4H(aq) + 3 e Mno" (aq) + 8 H(aq) + 5e Au(aq) + 3 e +ag) PbO (s) + 4H(aq) + 2 e Chlg) + 2e Cr20,-(aq) + 14 H+ (aq) + 6 19 Olg) + 4H(aq) + 4 e MnOz(s) + 4H(aq) + 2 e 10, (aq) + 6 H(aq) + 5e 9 loe Bral Bry() +2 e VO, (aq) + 2 H(aq) + NO, (aq) + 4H(aq) + 3 CIO(g) + e Ag+ (aq) + 6 Fel(aq) + Olg) + 2 H(aq) + 2 e MnO4 (aq) + 6 M. wa 12(s) + 2 e Cu (aq) + e 0,1g) + 2 H2O(l) + 48 cư Lag) + 2% SO?" (aq) + 4H+ (aq) + 2 e C++ (aq) + Sn* (aq) + 2 e 2H*(aq) + 2 e + Fe+ (aq) + 3e (+ 3 PV (aq) + 2 e Sn(aq) + 20 Ni2+ (aq) + 20 Cd(aq) + 2 e leder Fe(aq) + 20 от Cr+ (aq) + e Craq) + 3 e Zop* (aq) + 20 ? 2 H2O(l) + 2e Mr? (aq) + 2 e lara 2 F (aq) 2H00) PbSO4(s) + 2 H2011) MnOz(s) + 2 H2011) s) 2 ) Mr? (aq) + 4H2O(1) Au(s) — Pb (aq) + 2 H2011) 2 CI" (aq) - *) 2 Cr(aq) + 7 H2O1) 2H00) Mr?* aq) + 2 H2O11 ) blaq) + 3 H2011) - 2 Br"(aq) VO** (aq) + H2O(1) NO(g) + 2 H2O(1) CIO,(aq) Agis) Fe(aq) -H,O,(aq) — Mno? (aq) -2 (aq) -Cu(s) Gulsh — Cu(s) - H Sog(aq) + H2O(1) -Cut (aq) Sr?(aq) Helg Fe(s) - Pb(s) Sn(s) - Nils) - Cd(s) -Fe(s) -Crad) Cris) Zn(s) Halg) + 2 OH(aq) Mn(s) Al(s) - Mg(s) mala Na(s) Ca(s) - Ba(s) - Kis Lils) 0.96 0.9: O.AL 0.81 0.7 W. 07 0.70 0.50 0.54 0.51 0.4 0.34 4 OH(aq) 0.26 0.16 0.1! 0 -0.00 0.13 -0.14 -0.2: -0.40 -0.4 -0.56 -0.7: -0.70 -0.80 -1.18 -1.64 -2.3: -2.7 -2.74 -2.90 -2.9: -3.04 Al(aq) + 3e Mg? (aq) + 20 Na (aq) + 6 Co?(aq) + 20 Bar (aq) + 20 K(aq) + Lit(aq) + 0 O a.-12.8 Kj Ob 128 Kj OC. -128 Kj od 12.8 Kj