Example 4.11: One liter of an aqueous solution containing 0.010 mol of phenol is brought to equilibrium at 20°C with 5 g

[answerhappygod]

Example 4 11 One Liter Of An Aqueous Solution Containing 0 010 Mol Of Phenol Is Brought To Equilibrium At 20 C With 5 G 1 (22.86 KiB) Viewed 15 times

Example 4 11 One Liter Of An Aqueous Solution Containing 0 010 Mol Of Phenol Is Brought To Equilibrium At 20 C With 5 G 2 (38.72 KiB) Viewed 15 times

Example 4 11 One Liter Of An Aqueous Solution Containing 0 010 Mol Of Phenol Is Brought To Equilibrium At 20 C With 5 G 3 (37.15 KiB) Viewed 15 times

Example 4.11: One liter of an aqueous solution containing 0.010 mol of phenol is brought to equilibrium at 20°C with 5 g of activated carbon having the adsorption isotherm shown in Figure 4.25. Determine the per- cent adsorption of the phenol and the equilibrium concentrations of phenol on carbon by: (a) A graphical method
SOLUTION = = From the data given,c(") = 10 mmol/L, Q = 1 L, and S = 5 g. (a) Graphical method. From (4-29), 9g = -(1) CB + 10 (}) = -0.2CB + 2 This equation, with a slope of -0.2 and an intercept of 2, when plotted on Figure 4.25, yields an intersection with the equilib- rium curve at 9g = 1.9 mmol/g and cb = 0.57 mmol/liter. 9B g . Thus, the percent adsorption of phenol is - -CB (F) CB (F) 10 - 0.57 = 0.94 or 94% 10 CB
adsorption of phenol from an aqueous solution onto activated carbon at 20°C 4 mmole gram 3 2 Adsorption, q* 0 1 2 3 4 5 6 7 Equilibrium concentration, c, mmole liter