2. Select the correct answer from the following list and write the corresponding letter in the correct place in the tabl

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answerhappygod
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2. Select the correct answer from the following list and write the corresponding letter in the correct place in the tabl

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2 Select The Correct Answer From The Following List And Write The Corresponding Letter In The Correct Place In The Tabl 2
2 Select The Correct Answer From The Following List And Write The Corresponding Letter In The Correct Place In The Tabl 2 (84.07 KiB) Viewed 15 times
2 Select The Correct Answer From The Following List And Write The Corresponding Letter In The Correct Place In The Tabl 3
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2 Select The Correct Answer From The Following List And Write The Corresponding Letter In The Correct Place In The Tabl 4
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2. Select the correct answer from the following list and write the corresponding letter in the correct place in the table below: A B No reation will occur A carboxylic acid is formed An aldehyde is formed A ketone is formed с D Product 2.1 A primary (1°) alcohol is treated with a weaker oxidizing agent like pyridinium chlorochromate (PCC) in dichloromethane solution 2.2 A primary (1°) alcohol is treated with a strong oxidizing agent like sodium dichromate in acid solution 2.3 A secondary (2º) alcohol is treated with a strong oxidizing agent like sodium dichromate in acid solution 2.4 A tertiary (39) alcohol treated with a strong oxidizing agent like sodium dichromate in acid solution 3. Complete the following by writing oxidation or reduction in the appropriate block:
4. Classify each of the following reactions as oxidation or reduction and state the reagent that is needed to carry out each reaction: 1 CH3CH,сно CH2CH2CH2OH Oxidation or reduction: Reagent required: 4.2 CH3CH2CHO CH3CH2COOH Oxidation or reduction: Reagent required: 4.3 CO
Oxidation or reduction: Reagent required: Oxidation or reduction: Reagent required: Complete the mechanism for the reaction by using arrows to show the flow of electror
:0-H H₃ CC-H 11 Ho-Cr-OH + ee CH3 Orange coloured solution Cr(VI) O-H O.. :0-Cr-OH O=O=0 H3CC-H CH3 OH O=Cr=0 :9: H3C-C-H CH3 Water acts as base a Ht from the carbo 11 H3CC + HCrO3 H30+ CH3 o Il + H3CCCH3 + Cr3 + H2O Product Green coloured
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