3. A newly appointed biochemical engineer was tasked with inoculum preparation and scale up of a culture of a sensitive

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3 A Newly Appointed Biochemical Engineer Was Tasked With Inoculum Preparation And Scale Up Of A Culture Of A Sensitive 1 (102.39 KiB) Viewed 11 times

3. A newly appointed biochemical engineer was tasked with inoculum preparation and scale up of a culture of a sensitive bacterium strain. They undertook the following operating procedure: Step 1: Step 2: Step 3: They prepared the working culture of the bacterium on an agar slant, and waited for 1 day They added saline and glass beads to the slant, and waited for 1 day They transferred the culture to a shake flask preloaded with fresh agar, and waited for 1 day They transferred the culture to a seed fermenter and waited for 1 day They transferred the fermenter contents to the production fermenter Step 4: Step 5: (a) What was the purpose of the 1 day waiting time between steps? Use an appropriate sketch to support your explanation. [4 marks] (b) Tests carried out on the production fermenter indicated that the cell mass concentration was far below the level expected. Review the engineer's operating procedure and identify three possible reasons for this. [6 marks]
R = 8.3145J/mol K = 1.98 cal/mol K The formulae below are for the following reaction where A is the limiting reactant: aA + bB → CC + dD Excess Ratio: NBo a y = b Nao Kinetics: -Eact/RT (-ra) = KC AC3 k=Ae Conversion: Constant Volume Systems: C; = Cio + VCAOX CA = CAO(1 - x) Variable Volume Systems: E = y208 6-689- )- C d b -+---- ка a a а. = Vi i=1 Cio + viCAOX C = (1 + EX) (1 – X) CA = CAO (1 + EX) Design Equations: 影。 -X NAO Batch Reactor: t= dx JO (-A) V CSTR: V= FAOX (-ra) > T = Vo FAO PFR: V= so dx (مr-)
Numerical Integration: Χη Xnxo Trapezium Rule: ydx = Elyo +2(y, + y2 + y2 + ... + Yo-1) +yn]; n = [h n- n Хо -X2 h Simpson's Rule: = + ; h = X2 - Xo 2 Хо **tx = $ \x + 4%, + ve]n=**** ydx [48 (»-Mlvo , n-* L*ydx = '5lvo + 4y, + 2y2 + 4x +ya] n = *s ** n-- -X3 ydx = 3 8 h[y. + 3y, + 3y2 +y3]; h X3 – XO 3 Хо [4y2 ; h = X4 4