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Consider two rectangular surfaces perpendicular to each other with a common edge which is 1.6 m long. The horizontal surface is 0.8 m wide and the vertical surface is 1.2 m high. The horizontal surface has an emissivity of 0.75 and is maintained at 450 K. The vertical surface is black and is maintained at 700 K. The back sides of the surfaces are insulated. The surrounding surfaces are at 290 K, and can be considered to have an emissivity of 0.85. Determine the net rate of radiation heat transfers between the two surfaces, and between the horizontal surface and the surroundings. To = 700 K &z=1 W = 1.6 m L = 1.2 m A22 Tz = 290 K Ez = 0.85 L; = 0.8 mA, 0 Ti = 450 K & = 0.75 i FIGURE P21-91
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