2. Se considera bombear agua desde un tanque a otro tanque elevado, ambos tanques abiertos a la atmósfera como se muestra en la figura inferior. Además de los tanques, el sistema incluye un largo total de tubería de 90m de acero comercial nuevo de 15cm de diámetro, dos codos regulares roscados (“threaded”), una válvula de un solo paso y una bomba. El sistema debe producir un flujo de 40 L/s. Determine: (a) la velocidad del fluido en la tubería, (b) el número de Re, (c) el factor de fricción f usando la fórmula provista, (d) la altura equivalente que la bomba debe suplir al sistema P2 = Patm 18m valve, kv=4 P1 = Patm
e(mm) Loss Coefficients for Pipe Components h = K Component K. Pipe Material Glass, drawn brass, copper (new) Seamless commercial steel (new) Commercial steel (enamel coated) Commercial steel (new) Wrought iron (new) Asphalted cast iron (new) Galvanized iron Cast iron (new) Wood Stave (new) Concrete (steel forms, smooth) Concrete (good joints, average) Concrete (rough, visible, form marks) Riveted steel (new) Corrugated metal 0.0015 0.004 0.0048 0.045 0.045 0.12 0.15 0.26 0.18-0.9 0.18 0.36 0.60 0.9 - 9.0 45 Elbows Regular 90°, flanged Regular 90°, threaded Long radius 90°, flanged Long radius 90, threaded Long radius 45°, flanged Regular 45°, threaded 0.3 1.5 0.2 0.7 0.2 0.4 b. 180° return bends 180° return bend, flanged 180° return bend, threaded 0.2 1.5 Friction factor laminar flow 64.0 f = Rep For turbulent flow use the following relationship to find the friction factor: 0.25 f E 5.74 log + 3.7D Rep 0.9 Reentrant (embeded) Ki = 0.8 Sharp edge K = 0.5 Slightly rounded Kj = 0.2 Well rounded Kp = 0.04
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