6 A second order system is described by the following equation 14 ž() + 4 +kx(t)=r(t) X(s) The input-output transfer fun
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6 A second order system is described by the following equation 14 ž() + 4 +kx(t)=r(t) X(s) The input-output transfer fun
6 A second order system is described by the following equation 14 ž() + 4 +kx(t)=r(t) X(s) The input-output transfer function R(s) out of is a. X(s) R(s) 0.07143 $2+0.2857 s+ 1.857 O b. X(S) R(s) 0.07143 $2+0.5714 s+ 1.857 C. None O d. X(s) 0.07143 R(s) s?+0.2857 s+ 5.571 O e. x(s) X 0.03571 R(S) $2+0.2857 s+ 1.857
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