The three treatments in the experiment define three populations of interest. You use an ANOVA to test the hypothesis tha

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The three treatments in the experiment define three populations
of interest. You use an ANOVA to test the hypothesis that the three
population means are equal. Present the results of your analysis in
the following ANOVA table by entering the missing df values and
selecting the correct values for the missing SS, MS, and F entries.
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Attempts Average / 5 4. Repeated-measures ANOVA Suppose you are interested in studying whether lighting brightness affects spatial reasoning abilities. You decide to test spatial reasoning using completion time scores for the paper-folding test with five people, repeating the test on each person with three different lighting levels (800, 1,000, and 1,200 lux). In this experiment, the null hypothesis is that: There are no individual differences in the completion time means There are no differences in the mean completion times among the lighting levels compared The completion time mean for at least one lighting brightness is different from another The factor of interest is the lighting brightness , and the dependent variable is the completion time The results of the study are seconds. completion time wing data table. All scores are times necessary to complete the paper-folding task, recorded in lighting brightness participant
The results of the study are presented in the following data table. All scores are times necessary to complete the paper-folding task, recorded in seconds. Participant Totals Participant A A Lighting Brightness 800 lux 1,000 lux 1,200 lux 3.22 3.42 3.46 P = 10.10 n 5 B B 3.27 3.31 3.35 P = 9.93 k = 3 с 3.47 3.93 3.69 P = 11.09 N N = 15 D 3.43 3.91 3.74 P = 11.08 G 53.53 E 3.35 4.16 3.82 P = 11.33 ΣΧ2 192.1709 T = 16.74 T = 18.73 T = 18.06 SS = 0.0441 SS = 0.5286 SS = 0.1575 The three treatments in the experiment define three populations of interest. You use an ANOVA to test the hypothesis that the three population means are equal. Present the results of your analysis in the following ANOVA table by entering the missing df values and selecting the correct values for the missing SS, MS, and F entries. (Note: For best results, retain at least two additional decimal points throughout your calculations. Depending on the order in which you do these calculations and the number of digits you retain, you may find slight rounding differences in the last digit between your answers and the answer choices.)
SS df MS F ANOVA Table Source Between treatments Within treatments Between subjects Error Total 0.0609 0.1372 14 F Distribution Numerator Degrees of Freedom - 26 Denominator Degrees of Freedom = 26 .5000 .5000 - 0 T 2 - العا 3 1 7 4 5 6 8 9 1 1.00 F
.5000 .5000 0 1 2 3 4 5 6 8 9 1.00 F Use the Distributions tool to find the critical value for a = 0.01. The critical value is F = At a significance level of a = 0.01, evaluate the null hypothesis that the population means for all treatments are equal. The null hypothesis is You conclude that lighting brightness affects spatial reasoning abilities. Grade It Now Save & Continue