A new graduate working for a local company, is given the task of selecting suitable tapered roller bearings for the appl

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answerhappygod
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A new graduate working for a local company, is given the task of selecting suitable tapered roller bearings for the appl

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A New Graduate Working For A Local Company Is Given The Task Of Selecting Suitable Tapered Roller Bearings For The Appl 1
A New Graduate Working For A Local Company Is Given The Task Of Selecting Suitable Tapered Roller Bearings For The Appl 1 (67.72 KiB) Viewed 13 times
A New Graduate Working For A Local Company Is Given The Task Of Selecting Suitable Tapered Roller Bearings For The Appl 2
A New Graduate Working For A Local Company Is Given The Task Of Selecting Suitable Tapered Roller Bearings For The Appl 2 (56.22 KiB) Viewed 13 times
A New Graduate Working For A Local Company Is Given The Task Of Selecting Suitable Tapered Roller Bearings For The Appl 3
A New Graduate Working For A Local Company Is Given The Task Of Selecting Suitable Tapered Roller Bearings For The Appl 3 (79.46 KiB) Viewed 13 times
please solve the rest of the problem
A new graduate working for a local company, is given the task of selecting suitable tapered roller bearings for the application shown in the figure below. He/she is to select the bearing from Timken Co. Catalog given in the textbook. He/She is also given the following information about the applicati 1. 2. The shaft is also subject to a thrust load of 10 kN as shown in the figure. 3. The shaft rotates at 600 rpm 4. The shaft is in a piece of a machine designed for short operations of 5 kh. 5. The reliability goal for the bearing set is 96%. Show all your work. 20 kN radial load Commercial Gear style 10 kN Thrust load H 150 mm -100 mm 250 mm
for a single δώ ,equution gwen by →P = xofr + Yofa we have X=0.5 Yo = 1.2 fr=20kN fx fa = 5KN :: P = 0.5 x 20 + 1.2*5 - 16000 other factors Determining i KS = 3 350 : 0.88 500 $ ka rii ap1.34 . = CRI (laad) = px ka x kpx ks x1 16000 XI SX 1.34 X 0.88 X1 CRI : 28 300N =>
or in one gow radici [Ckı = 41200N) [ da y por double row, finding p P = xofr + Yofa IX20 + 2.485 p. = 32000 .: CR2 = Px Ks x kax kpx Рx | : CR2 - 32000X 1.5 X 1.34 X0F8X1 [CR2 = 56, 601:6N ] or for two row rackeil [ord - 71900N] - K:15, forcra cording to the enginees the data is incorrect for a moderati shock wawe hence it is not aceptable
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