vt . = Uo - 2K SA = at the interface (z= 0), TT a • To ~ 0.002Pair (Vwind – uo)2 (Roll 1965) → Uo ~0.6m/s after 1min and

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answerhappygod
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vt . = Uo - 2K SA = at the interface (z= 0), TT a • To ~ 0.002Pair (Vwind – uo)2 (Roll 1965) → Uo ~0.6m/s after 1min and

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Vt Uo 2k Sa At The Interface Z 0 Tt A To 0 002pair Vwind Uo 2 Roll 1965 Uo 0 6m S After 1min And 1
Vt Uo 2k Sa At The Interface Z 0 Tt A To 0 002pair Vwind Uo 2 Roll 1965 Uo 0 6m S After 1min And 1 (78.87 KiB) Viewed 22 times
When V=6 m/s, calculate the u0 value after one hour to three
decimal places
vt . = Uo - 2K SA = at the interface (z= 0), TT a • To ~ 0.002Pair (Vwind – uo)2 (Roll 1965) → Uo ~0.6m/s after 1min and 2.3m/s after 1h for a wind speed of 6m/s • For actual flow of this type, uo 0.2m/s after 1h • The discrepancy is due to the fact that this type of large scale flow is usually turbulent.
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