vt . = Uo - 2K SA = at the interface (z= 0), TT a • To ~ 0.002Pair (Vwind – uo)2 (Roll 1965) → Uo ~0.6m/s after 1min and

[answerhappygod]

Vt Uo 2k Sa At The Interface Z 0 Tt A To 0 002pair Vwind Uo 2 Roll 1965 Uo 0 6m S After 1min And 1 (78.87 KiB) Viewed 12 times

Suppose u0 = 0.200 m/s for the actual turbulent flow, and
ueffective = Assuming ulaminar+uturbulence, find out how many times
the uurbulence is to obtain u0 = 0.200 m/s from the above
equation
vt . = Uo - 2K SA = at the interface (z= 0), TT a • To ~ 0.002Pair (Vwind – uo)2 (Roll 1965) → Uo ~0.6m/s after 1min and 2.3m/s after 1h for a wind speed of 6m/s • For actual flow of this type, uo 0.2m/s after 1h • The discrepancy is due to the fact that this type of large scale flow is usually turbulent.