- 3 M B D D The Slender Rod Has A Mass M Ab 20kg And The Point Mass Has A Mass M A 10kg Bonded At The Bottom Of The Rod Ab 1 (32.43 KiB) Viewed 14 times
3 m B d D The slender rod has a mass m AB=20kg and the point mass has a mass m A=10kg bonded at the bottom of the rod AB
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3 m B d D The slender rod has a mass m AB=20kg and the point mass has a mass m A=10kg bonded at the bottom of the rod AB
3 m B d D The slender rod has a mass m AB=20kg and the point mass has a mass m A=10kg bonded at the bottom of the rod AB. This combined group is suspended at its end B by a cord. If the rod receives a horizontal blow giving it an impulse I=60 N.s at its bottom A: a. Determine the location of the center of mass relative to point A b. Determine the mass moment of inertia of the combined rod and point mass c. Determine the location d of the point D about which the rod and point mass appears to rotate during the impact. rod S A poiit mass impulse Note that the rod starts from rest. • Irod = mx 1? • lend rod = mx 1? • IG point mass = 0 • Parallel axis theorem: Ip = IG+mxre to G