R=502 C=15 LF im L-0.3 H Vmax = 25 V f-50 Hz

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answerhappygod
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R=502 C=15 LF im L-0.3 H Vmax = 25 V f-50 Hz

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R 502 C 15 Lf Im L 0 3 H Vmax 25 V F 50 Hz 1
R 502 C 15 Lf Im L 0 3 H Vmax 25 V F 50 Hz 1 (6.06 KiB) Viewed 15 times
Resistor Resistance, R=50 Ω
Inductor Inductance, L=0.3 H
Capacitor Capacitance, C=15 × 10^(-6) F
Peak Voltage, V_max=25 V Frequency, f=50 Hz
Φ=arctan(2.4) =67^∘=1.17 rad I_max=0.2 A
Questions:
a. Determine the voltage across the Resistor, VR(t). Hint: VR(t)
is in phase with I(t). What is the average voltage across the
resistor, VR?
b. Determine the voltage across the Inductor, VL(t). Hint: VL(t)
leads VR(t) by 90 degrees. What is the average voltage across the
inductor, VL?
c. Determine the voltage across the Capacitor, VC(t). Hint:
VC(t) lags VR(t) by 90 degrees. What is the average voltage across
the capacitor, VC?
d. Show that V ≠ VR + VL + VC e. Determine the power used in the
circuit.
R=502 C=15 LF im L-0.3 H Vmax = 25 V f-50 Hz
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