7. Given a QPSK signal Vopsk(t) = 2b.(t)sin(20 x 10$t) +2b.(t)cos(2 x 105t) where b. (0),be(t) take a value of -1 or 1 e

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7 Given A Qpsk Signal Vopsk T 2b T Sin 20 X 10 T 2b T Cos 2 X 105t Where B 0 Be T Take A Value Of 1 Or 1 E 1 (26.69 KiB) Viewed 14 times

7. Given a QPSK signal Vopsk(t) = 2b.(t)sin(20 x 10$t) +2b.(t)cos(2 x 105t) where b. (0),be(t) take a value of -1 or 1 every 6 seconds. For Vopsk), determine (1) (5%) signal power Ps; (2) (5%) symbol period T, and bit period Tb; (3) (5%) nominal bandwidth BQPk; (4) (5%) energy per symbol E, and energy per bit Eb; (5) (5%) minimum distance between symbols dopsk