7. Given a QPSK signal Vopsk (t) = 2b.(t)sin(21 x 105 t) + 2be(t)cos(210 x 105t) where b.(t), b (t) take a va of -1 or 1

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7 Given A Qpsk Signal Vopsk T 2b T Sin 21 X 105 T 2be T Cos 210 X 105t Where B T B T Take A Va Of 1 Or 1 1 (19.67 KiB) Viewed 22 times

7. Given a QPSK signal Vopsk (t) = 2b.(t)sin(21 x 105 t) + 2be(t)cos(210 x 105t) where b.(t), b (t) take a va of -1 or 1 every 6 seconds. For VQpsk (t), determine (1) (5%) signal power Ps; (2) (5%) symbol period T, and bit period To: (3) (5%) nominal bandwidth BQPK: (4) (5%) energy per symbol E, and energy per bit Ebi (5) (5%) minimum distance between symbols dopsk