- S3 35p In The Circuit In The Figure Vod 121 Is Given As R 50k R2 10k Rd Rg Ik R 3k The Amplitude Of The Smal 1 (42.25 KiB) Viewed 24 times
- S3 35p In The Circuit In The Figure Vod 121 Is Given As R 50k R2 10k Rd Rg Ik R 3k The Amplitude Of The Smal 2 (41.74 KiB) Viewed 24 times
- S3 35p In The Circuit In The Figure Vod 121 Is Given As R 50k R2 10k Rd Rg Ik R 3k The Amplitude Of The Smal 3 (37.26 KiB) Viewed 24 times
S2) (35p) In the circuit in the figure, as R=2.08k R=2.08k2, R=105.9k2, R2-20.4k2, R 10.8 R25k, &m=38.9mA/V,r=9k, C =15pF, C=1pF is given. Given that the amplifier's lower cutoff frequency is o =200rad / s: a) Draw the AC equivalent circuits of the amplifier for low frequencies and high frequencies separately b) By taking the A coefficient value of 4-15-according to the last two digits (xx) of your student the values of C, and C, given that xx 10 = 4.0 and it is accepted that the effect of C, can be neglected in the calculation of the lower cutoff frequency R G 7 с w 11 Rc w RI WWW R ww HH ww R2 ve 바
S1 (30p) In the circuit in the figure, the parameters of Zener diodes with the same characteristics are given as Vzo=4+0.08.xx V and V,-0.6+2x10xx V according to the last two digits (xx) of your student number (r=0). Accordingly, change Vor=f(vin) for the range -20 <v <201 (horizontal axis v to vertical axis v) R a) When Z1 and 22 are connected as in the figure, b) www When only Z1 is connected to the output Draw to scale for the situations. zi IN KDHI X2