Mounting the circuit in Figure 1 in Tinkercad, the OPAMP output should model the following equation Y = 4X – 2 (Adder -

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answerhappygod
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Mounting the circuit in Figure 1 in Tinkercad, the OPAMP output should model the following equation Y = 4X – 2 (Adder -

Post by answerhappygod »

Mounting the circuit in Figure 1 in Tinkercad, the OPAMP output should model the following equation
Y = 4X – 2 (Adder - Subtractor).
Criteria for Design:
V1= is the voltage of the RL charge.
V2 = is variable.
Polarization of the Operational Amplifier V+ = +15 V and V- = -15V.
V3, R3, R4, R5, RL at the discretion of the designer.
R1, R2, RF1, RF2, RX (if necessary), all these resistors are at the discretion of the designer,
looking for the values that meet the expected output from the equation given.
The entire circuit operates with direct current (DC Voltage).
For the output of the OPAMP they will have a margin of error between + – 0.8.
Example:
Y = 4X – 2, if X = 2 then Y = 6.
Vout = 4V2 – 2, if V2 = 2 then Vout = 6V. However, the result can be between 6.8 and 5.2.
Mounting The Circuit In Figure 1 In Tinkercad The Opamp Output Should Model The Following Equation Y 4x 2 Adder 1
Mounting The Circuit In Figure 1 In Tinkercad The Opamp Output Should Model The Following Equation Y 4x 2 Adder 1 (82.45 KiB) Viewed 12 times
You must fill in the following table of results, for the different values of V2:
Mounting The Circuit In Figure 1 In Tinkercad The Opamp Output Should Model The Following Equation Y 4x 2 Adder 2
Mounting The Circuit In Figure 1 In Tinkercad The Opamp Output Should Model The Following Equation Y 4x 2 Adder 2 (82.45 KiB) Viewed 12 times
V2 0.5 1 1.5 2. 2.5 3 3.5 4 Vout
V2 0.5 1 1.5 2. 2.5 3 3.5 4 Vout
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