- 5 10 Consider A Signal V T B T Cos W T As In The Figure B T Bx Forte K 1 T Kt And Bk 1 1 1 1 F 1 (19.64 KiB) Viewed 13 times
5. (10%) Consider a signal v(t) = b(t)cos? (w.t + ). As in the figure, b(t) = bx forte ((k-1)T),kT) and bk = 1,-1,-1,1 f
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5. (10%) Consider a signal v(t) = b(t)cos? (w.t + ). As in the figure, b(t) = bx forte ((k-1)T),kT) and bk = 1,-1,-1,1 f
5. (10%) Consider a signal v(t) = b(t)cos? (w.t + ). As in the figure, b(t) = bx forte ((k-1)T),kT) and bk = 1,-1,-1,1 for k = 1,2,3,4 with 1/T) « fo. v(t) passes through an integrator that takes integration on v(t) for every Ty seconds and outputs v.(kt) for k = 1,2,3,4. Determine v.(kt) for k = 1,2,3,4 with your derivations. b(t) 1 -1 -1 1 1 3 4 0 t(T)