S.C Zo = 10022 50 Ω Q32 A 50-MHz generator with Zg = 50 2 is connected to a load Z = 50 - 125 12. The time-average power

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

S.C Zo = 10022 50 Ω Q32 A 50-MHz generator with Zg = 50 2 is connected to a load Z = 50 - 125 12. The time-average power

Post by answerhappygod »

1
1 (131.39 KiB) Viewed 17 times
S.C Zo = 10022 50 Ω Q32 A 50-MHz generator with Zg = 50 2 is connected to a load Z = 50 - 125 12. The time-average power – transferred from the generator into the load is maximum when Zg = Zi, where Zi is the complex conjugate of ZL. To achieve this condition without changing Zg, the effective load impedance can be modified by adding a short-circuited (S.C) line in series with Zł, as shown in the figure. If the line's Zo = 1002, determine the shortest length of line (in wavelength) necessary for satisfying the maximum-power-transfer condition. Answer: TE ZL 50-7.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Top
Post Reply

Return to “Archived Questions & Answers”