The customer lifts Say each in cames up to 600 kg (mat's the car and a few people). The lift is operated by a motor and

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answerhappygod
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The customer lifts Say each in cames up to 600 kg (mat's the car and a few people). The lift is operated by a motor and

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The Customer Lifts Say Each In Cames Up To 600 Kg Mat S The Car And A Few People The Lift Is Operated By A Motor And 1
The Customer Lifts Say Each In Cames Up To 600 Kg Mat S The Car And A Few People The Lift Is Operated By A Motor And 1 (34.28 KiB) Viewed 58 times
The Customer Lifts Say Each In Cames Up To 600 Kg Mat S The Car And A Few People The Lift Is Operated By A Motor And 2
The Customer Lifts Say Each In Cames Up To 600 Kg Mat S The Car And A Few People The Lift Is Operated By A Motor And 2 (17.1 KiB) Viewed 58 times
The Customer Lifts Say Each In Cames Up To 600 Kg Mat S The Car And A Few People The Lift Is Operated By A Motor And 3
The Customer Lifts Say Each In Cames Up To 600 Kg Mat S The Car And A Few People The Lift Is Operated By A Motor And 3 (15.94 KiB) Viewed 58 times
The customer lifts Say each in cames up to 600 kg (mat's the car and a few people). The lift is operated by a motor and a counterweight as shown in Figure 1 We want to calculate the force the DC motor must provide to power the in according to our client's specifications. We want to specify the power rating of the motor FEN m = 200 kg FRN 2009 600 kg 600g Figure 1 Force diagram for the litt system adapted from 1 T is the tension in the cables is me acceleration due to gravity which we w take as 10ms! Fis the force exerted by the motor Here's the specification • Total 1 mass is 600 kg, counterweight is 200 kg • Acceleration of 2 ma over 0.5 to a speed of 1 ms Steady speed between the floors of 1 ms 1 for 40 .Decelerate at 2 m -2 over 0.5 to a stop 1

Q1. Force and power required for acceleration upwards We can write two simultaneous equations, one for the life going up, one for the counterweight going down. When the aft is going up, its acceleration a is in the positive direction (upwards) The counterweight is accelerating downwards at the same rate, it's acceleration is negative because of the direction downwards For the counterweight T - 200 g - 200 a ( For the in T + F 600 9 = 600 a (2) Solving, we find T = 1600 N and hence F-5600 N

Q3. Force and power required for decceleration You need to rewrite equations (1) and (2) with change of sign for the acceleration The tension in the cable is 2400 N [1 mark] The force required from the motor is 2400 N f1 mark The power required from the motoris Number w [1 mark
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