The Customer Lifts Say Each Ift Carries Up To 600 Kg That S The Car And A Few People The Art Is Operated By A Motor A 1 (37.24 KiB) Viewed 40 times
The Customer Lifts Say Each Ift Carries Up To 600 Kg That S The Car And A Few People The Art Is Operated By A Motor A 2 (33.2 KiB) Viewed 40 times
The customer lifts Say each ift carries up to 600 kg (that's the car and a few people). The art is operated by a motor and a counterweight, as shown in Figure 1. We want to calculate the force F the DC motor must provide to power the lift according to our client's specifications. We want to specify the power rating of the motor F KN m= 200 kg V 天 FAN 200g m 600 kg 600g Figure 1 Force diagram for the system, adapted from / T is me tension in the cables, is the moceleration due to gravity which well take as toms Fis me force exerted by the motor Here's the specification Total mass is 600 kg, counterweight is 200 kg • Acceleration of 2 mx -2 over 0.5 to a speed of me 1 • Steady speed between the floors of me ford .Decelerate at 2 m -2 over 0.5 to a stop
We need to work out the requirements for the motor over these 5 seconds, to move up one floor Q1. Force and power required for acceleration upwards. We can write two simultaneous equations, one for the in going up one for the counterweight going down. When the it is going up, its acceleration a is in the positive direction (upwards). The counterweight is accelerating downwards at the same rate, it's acceleration is negative because of the direction downwards For the counterweight, T 200 g -200 a For the line T + F - 6000 600 a (2 ) Solving, we find T 1600 N and hence F - 5600 N How much power do we need? Enter your answer as an integer [1 mark The power required from the motor is Number w
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