10.20m 0.20m 0.20m 10.2om 10.1om/21 Experiment KI Nach Naz520 /starch K2504 K ₂ S₂08 . 2.0 2.0 2.0 12.o 1.0 2.0 2.o 2 2.

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answerhappygod
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10.20m 0.20m 0.20m 10.2om 10.1om/21 Experiment KI Nach Naz520 /starch K2504 K ₂ S₂08 . 2.0 2.0 2.0 12.o 1.0 2.0 2.o 2 2.

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10 20m 0 20m 0 20m 10 2om 10 1om 21 Experiment Ki Nach Naz520 Starch K2504 K S 08 2 0 2 0 2 0 12 O 1 0 2 0 2 O 2 2 1
10 20m 0 20m 0 20m 10 2om 10 1om 21 Experiment Ki Nach Naz520 Starch K2504 K S 08 2 0 2 0 2 0 12 O 1 0 2 0 2 O 2 2 1 (52.36 KiB) Viewed 119 times
10 20m 0 20m 0 20m 10 2om 10 1om 21 Experiment Ki Nach Naz520 Starch K2504 K S 08 2 0 2 0 2 0 12 O 1 0 2 0 2 O 2 2 2
10 20m 0 20m 0 20m 10 2om 10 1om 21 Experiment Ki Nach Naz520 Starch K2504 K S 08 2 0 2 0 2 0 12 O 1 0 2 0 2 O 2 2 2 (42.38 KiB) Viewed 119 times
10.20m 0.20m 0.20m 10.2om 10.1om/21 Experiment KI Nach Naz520 /starch K2504 K ₂ S₂08 . 2.0 2.0 2.0 12.o 1.0 2.0 2.o 2 2.0 2.0 O 4.0 4.0 2.0 3 0 2.0 1.o 2.0 Temp of labortery 216 Experiment Experiment 2 | Experiment Time it Time it changed Time it changed Changed Coir Color 1:51 Mannen Color 3:31 1:45 Triala Time it changed color Experiment 1 Exponiment 2 Experiment 3 3:49 1:23 1:37
Calculations 1. Calculate the elapsed time for each trial of each experiment (At = Time ended - time started). Calculate each trial and then average the results for the three separate experiments. 2. Calculate the initial concentrations of the Na2S2O3, K,S,Os, and Nal. Calculate each experiment and each trial and then average the two trials together for each of the above. (Remember each is diluted in the test tube). 3. Calculate the initial rates for Experiment 1, 2, and 3 A[ S203?"J/At using the average elapsed time for each experiment. Reread the intro on how to do this. 4. Obtain the reaction orders with respect to S,O, and I ions. Remember that your results have been influenced by experimental error (round to the nearest whole number). 5. What is the correct rate law equation? 6. Calculate the rate constant in Experiment 1, 2, and 3 and obtain the average rate constant.
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