Consider the following C++ code: double modifyValue (double value) { value = value * 2.0; return value; } double modifyR

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Consider The Following C Code Double Modifyvalue Double Value Value Value 2 0 Return Value Double Modifyr 1 (63.47 KiB) Viewed 34 times

Consider The Following C Code Double Modifyvalue Double Value Value Value 2 0 Return Value Double Modifyr 2 (46.12 KiB) Viewed 34 times

Consider the following C++ code: double modifyValue (double value) { value = value * 2.0; return value; } double modifyResult(double result) { result result / 3.0; if (result < 10) return result; else return modifyValue(result); } int main() { double value, result; value = 42; result = modifyValue (value); cout << value << " " << result << endl; // Position A result 36; value modifyResult(result); cout << value << " " << result << endl; // Position B return 0; 3 What values will be printed at Position A? What values will be printed at Position B?

result 36; value = modifyResult(result); cout << value << " << result << endl; / Position B return 0; [Choose ] } 84.0 84.0 12.0 36.0 What values will be printed at P 42.0 36.0 24.0 36.0 What values will be printed at P 42.0 84.0 42.0 42.0 42.0 24.0 36.0 84.0 Position A [Choose ] > Position B [Choose 1 <