Help!!

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Help!!

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Consider a paging system that supports a 5-bit logical address and has 64 bytes physical memory. The size of a page is 4 bytes. (b) (5 points) If the size of a page table entry is 2 bytes (first byte for frame number & second byte for protection bits), then how many bytes are required for a page table? (c) (10 points) The following figure shows the physical memory content and the 3rd page table (three- level paging) of a process. Fill the logical content of the process.

Logical address content Physical address content content 0 0 1 1 32 1 1 register-based MMU 3rd page table 3 3 1 3 33 3 8 2 1 2 34 3 3 0 4 5 3 35 5 4 1 2. 4 7 36 8 5 1 5 0 37 0 9 6 2 38 5 7 7 5 39 2 8 Frame ID Protection bits 8 CO 40 0 9 10 (b 15 10 1 9 13 3 4 8 9 3 41 3 10 10 9 10 42 7 e 2 11 11 5 43 5 12 5 15 12 4 44 15 13 10 13 1 45 1 14 1 3 14 7 46 12 $ 12 15 15 3 47 3 0 16 16 9 48 3 2 o 17 17 4 49 4 다. 12. 18 18 50 5 > 5 19 3 19 6 1 51 6 20 20 8 52 8 4 1 21 21 10 53 10 13 22 22 18 54 16 14 23 23 15 55 15 24 24 13 56 2 25 25 4 57 4 6 6 26 28 9 58 6 14 27 27 9 59 8 2 4 th X 13 4 9 9 28 28 14 60 11 29 29 7 61 7 30 6 62 9 30 31 31 63 13 13