Question 3 In Engineering An Equation Of State Is A Thermodynamic Equation Relating State Variables Which Describe The 1 (245.17 KiB) Viewed 34 times
Question 3 In Engineering, an equation of state is a thermodynamic equation relating state variables which describe the state of matter under a given set of physical conditions, such as pressure, volume, temperature (PVT). One of the commonly used equation of state is the Peng- Robinson equation, = RT p= v-h (v2 + dv+€ b + According to the Peng-Robinson equation of state, find the molar volume of propane at 300K and 10 bar using the bisection method, where PC Z = 0.2762 T = 369.83K = 42.48bar ve = 200.0cm’mol-1 0= 0.152 8= 25 &=-62 b=0.0778 a = 0.45724 R’T? Р. Р. O = a[1 +(0.37464+1.542260 – 0.26992002/1 – T42) RTC с = Use the attached spreadsheet (pengRobinsonVolume.xlsx « ), in which all required values are defined.
H +&+) bp RI 0-a[1 w/1-(14)")] A B C D E F G Н. 1 Numerical methods for solving nonlinear equations 2 Bisection method 3 4 Example with real gases 5 6 Find the molar volume of propane at 300 K and 10 bar by using the following Eos. 7 8 RT 9 10 P V- -B 11 12 13 PV P = 0.45724; = 0.0778, S= 25; &=-b2 14 RI (RT) 15 16 O= a 1+ (0.37464 +1.5422 W-0.2699 w 17 18 19 20 where 21 Properties of the fluid Conditions 22 23 T 369.8300 K T 300K 42.480 bar P 10 bar 200.000 cm/mol 26 Z 0.276 27 0.152 28 29 Parameters in Eos 30 31 R 83.1447 bar cm molt =0.45724B31^2*B2342/B24 bar cm mol 33 b =0.0778*B31*B23/B24 cm mol? 1 34 5 =2*B33 cm moi 35 € =-(B3342) cm mol 36 0 =B32*(1+0.37464+1.5422*B27-0.2699*B2742)*(1-(G23/B23)^0.5))^2 bar cm molk 37 38 24 PS 25 V 32 a 39 V: P PI-P V P P-P V P PP error do
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