Table 3.1 Mass of cart = 117.6cm Equilibrium position = 10,50kg Added Mass Position Force (mg) Displacement from Equilib

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answerhappygod
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Table 3.1 Mass of cart = 117.6cm Equilibrium position = 10,50kg Added Mass Position Force (mg) Displacement from Equilib

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Table 3 1 Mass Of Cart 117 6cm Equilibrium Position 10 50kg Added Mass Position Force Mg Displacement From Equilib 1
Table 3 1 Mass Of Cart 117 6cm Equilibrium Position 10 50kg Added Mass Position Force Mg Displacement From Equilib 1 (26.58 KiB) Viewed 34 times
Table 3 1 Mass Of Cart 117 6cm Equilibrium Position 10 50kg Added Mass Position Force Mg Displacement From Equilib 2
Table 3 1 Mass Of Cart 117 6cm Equilibrium Position 10 50kg Added Mass Position Force Mg Displacement From Equilib 2 (22.42 KiB) Viewed 34 times
Table 3.1 Mass of cart = 117.6cm Equilibrium position = 10,50kg Added Mass Position Force (mg) Displacement from Equilibrium 0 0 kg 20g 40g 60₂ 0 120.2cm 123.2cm 125.5cm 128.9cm 2.6cm 5.6cm 7.9cm 11.3com 0 0.196N 0.392N 6.588N sty 0.284N
LailuidLIUNTS Theoretical Period Using the data in Table 3.1. plot force versus displacement. Draw the best-fit straight line through the data points and determine the slope of the line. The slope is equal to the effec- tive spring constant, k. k 2 Using the mass of the cart and the spring constant, calculate the period using the theoretical formula. Also calculate the theoretical period for the cart with the 500 g mass in it. RTV m R (cart alone) T = (cart with mass) T = PASC 12 Scienti
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