Suppose a 250 ml flask is filled with 0.40 mol of NO, and 1.4 mol of NO. The following reaction becomes possible: NO,()+
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Suppose a 250 ml flask is filled with 0.40 mol of NO, and 1.4 mol of NO. The following reaction becomes possible: NO,()+
Suppose a 250 ml flask is filled with 0.40 mol of NO, and 1.4 mol of NO. The following reaction becomes possible: NO,()+NO(g) + 2NO2(g) The equilibrium constant K for this reaction is 3.78 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places. Ом х 5 ?
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