1. You dissolved 0.587 g of an unknown solid acid in 20.00 mL of water, then added a few drops of phenolphthalein indica

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answerhappygod
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1. You dissolved 0.587 g of an unknown solid acid in 20.00 mL of water, then added a few drops of phenolphthalein indica

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1 You Dissolved 0 587 G Of An Unknown Solid Acid In 20 00 Ml Of Water Then Added A Few Drops Of Phenolphthalein Indica 1
1 You Dissolved 0 587 G Of An Unknown Solid Acid In 20 00 Ml Of Water Then Added A Few Drops Of Phenolphthalein Indica 1 (15.97 KiB) Viewed 59 times
1 You Dissolved 0 587 G Of An Unknown Solid Acid In 20 00 Ml Of Water Then Added A Few Drops Of Phenolphthalein Indica 2
1 You Dissolved 0 587 G Of An Unknown Solid Acid In 20 00 Ml Of Water Then Added A Few Drops Of Phenolphthalein Indica 2 (32.98 KiB) Viewed 59 times
1. You dissolved 0.587 g of an unknown solid acid in 20.00 mL of water, then added a few drops of phenolphthalein indicator to the solution. It then took exactly 29.65 mL of 0.100 5 N NaOH to reach the equivalence point. What is the equivalent weight of the unknown acid? 十 0.DON 29.65-20.0-9.65m2 20.00ML nar
9 9 imo! 4. Assume you have the following calibration curve formed from your observations of the Mercury (Hg) emission spectrum. What is the corrected wavelength for an observed + value of 420 nm on the Hydrogen (HI) spectrum? What is its frequency? (Speed of light, c=2.99 x 10 m/s) Calibration Curve 420mmx. 10-9 600 inM The corrected have length is o gasa 420x10-9 500 Literature Wavelength (nm) y=0.9046x - 31.197 R' = 0.9969 400 300 300 700 400 500 600 Observed Wavelength (nm) E = hf Each C=Yf CEF (3.0x108) 420 X10-4 = 7.148 1014 frequency Y
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