To prepare the buffer in the previous problem, a total volume of 550 mL is required. The stock solution of the weak base

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answerhappygod
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To prepare the buffer in the previous problem, a total volume of 550 mL is required. The stock solution of the weak base

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To prepare the buffer in the previous problem, a total volume of
550 mL is required. The stock solution of the weak base is
available at 1 gallon with a concentration of 0.98 M. (Remember the
lesson on dilution: M1V1=M2V2)
How many mL should be taken from the stock solution to
prepare the desired buffer solution? (Write
your answer in 3 decimal places without the unit).
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